Math, asked by manas10960, 7 months ago

square root of 0.9 explain briefly​

Answers

Answered by skullcrusher1202
1

We must set an error for the final result. Say, smaller than 0.001. In other words we will try to find the square root value with at least 2 correct decimal places.

Step 1:

Divide the number (0.9) by 2 to get the first guess for the square root .

First guess = 0.9/2 = 0.45.

Step 2:

Divide 0.9 by the previous result. d = 0.9/0.45 = 2.

Average this value (d) with that of step 1: (2 + 0.45)/2 = 1.225 (new guess).

Error = new guess - previous value = 0.45 - 1.225 = 0.775.

0.775 > 0.001. As error > accuracy, we repeat this step again.

Step 3:

Divide 0.9 by the previous result. d = 0.9/1.225 = 0.7346938776.

Average this value (d) with that of step 2: (0.7346938776 + 1.225)/2 = 0.9798469388 (new guess).

Error = new guess - previous value = 1.225 - 0.9798469388 = 0.2451530612.

0.2451530612 > 0.001. As error > accuracy, we repeat this step again.

Step 4:

Divide 0.9 by the previous result. d = 0.9/0.9798469388 = 0.9185108045.

Average this value (d) with that of step 3: (0.9185108045 + 0.9798469388)/2 = 0.9491788717 (new guess).

Error = new guess - previous value = 0.9798469388 - 0.9491788717 = 0.0306680671.

0.0306680671 > 0.001. As error > accuracy, we repeat this step again.

Step 5:

Divide 0.9 by the previous result. d = 0.9/0.9491788717 = 0.9481879831.

Average this value (d) with that of step 4: (0.9481879831 + 0.9491788717)/2 = 0.9486834274 (new guess).

Error = new guess - previous value = 0.9491788717 - 0.9486834274 = 0.0004954443.

0.0004954443 <= 0.001. As error <= accuracy, we stop the iterations and use 0.9486834274 as the square root.

pls mark as BRAINILIEST.

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