square root of 1 minus sign Tita by 1 +sin tita is equal to secant tita - tan tita. prove
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Answer:
L.H.S
√[ (1 - Sin∆) / (1 + Sin∆) ]
= √[ (1 - Sin∆) × (1 - Sin∆) / (1 + Sin∆) × (1 - Sin∆) ]
= √[ (1 - Sin∆)^2 / (1^2 - Sin^2∆) ]
= √[ (1 - Sin∆)^2 / Cos^2∆ ]
= (1 - Sin∆) / (Cos∆)
= (1/Cos∆) - (Sin∆ / Cos∆)
= Sec∆ - Tan∆
= R.H.S (Proved)
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