Question

square root of 1 minus sign Tita by 1 +sin tita is equal to secant tita - tan tita. prove​

Answer 1

Answer:

L.H.S

√[ (1 - Sin∆) / (1 + Sin∆) ]

= √[ (1 - Sin∆) × (1 - Sin∆) / (1 + Sin∆) × (1 - Sin∆) ]

= √[ (1 - Sin∆)^2 / (1^2 - Sin^2∆) ]

= √[ (1 - Sin∆)^2 / Cos^2∆ ]

= (1 - Sin∆) / (Cos∆)

= (1/Cos∆) - (Sin∆ / Cos∆)

= Sec∆ - Tan∆

= R.H.S (Proved)