Math, asked by anjalipillay04, 6 months ago

square root of 16x^6-32x^3y^3+16y^6-16x^3z^3+16y^3z^3+4z^6​

Answers

Answered by sritarutvik
0

Step-by-step explanation:

16x^6-32x^3y^3+16y^6-16x^3z^3+16y^3z^3+4z^6

=(4×^3)^2+(4y^3)^2+(2z^3)^2-2(4x^3)(4y^3)+2(4y^3)(2z^3)-2(2z^3)(4x^3)

=(4x^3-4y^3-2z^3)^2

square root of 16x^6-32x^3y^3+16y^6-16x^3z^3+16y^3z^3+4z^6

=4x^3-4y^3-2z^3

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