Question

Square root of 2025 + square root of 0.0612+x=45.25. Find the value of x

Answer 1

The value of x is 0.0013.

Step-by-step explanation:

The expression is:

$\sqrt{2025}+\sqrt{0.0612+x}=45.25$

Solve for x as follows:

$\sqrt{2025}+\sqrt{0.0612+x}=45.25\\45+\sqrt{0.0612+x}=45.25\\\sqrt{0.0612+x}=45.25-45\\\sqrt{0.0612+x}=0.25\\0.0612+x=0.25^{2}\\0.0612+x=0.0625\\x=0.0625-0.0612\\x=0.0013$

Thus, the value of x is 0.0013.

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Answer 2

Answer:

Step-by-step explanation:

The expression is:

\sqrt{2025}+\sqrt{0.0612+x}=45.25\\

Solve for x as follows:

\sqrt{2025}+\sqrt{0.0612+x}=45.25\\45+\sqrt{0.0612+x}=45.25\\\sqrt{0.0612+x}=45.25-45\\\sqrt{0.0612+x}=0.25\\0.0612+x=0.25^{2}\\0.0612+x=0.0625\\x=0.0625-0.0612\\x=0.0013

Thus, the value of x is 0.0013.