Question

square root of 28 x square root of 24 bar square root of 42 x square root of 8​

Answer 1

Answer:

Step-by-step explanation:

Clearly the roller is a right circular cylinder of height h=120 cm

and radius of its base =r=42 cm

∴ area covered by the roller in one revolution = curved surface area of the roller 

           =2×722​×42×120cm2=31680cm2

so, area covered by the roller is 500 revolution = (31680×500)cm2

                    =100×10031680×500​m2=1584m2

hence , cost of levelling the playground = 1584×10030​=Rs475.20