Square root of 7921 in prime factorization method
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Answered by
13
Heya User,
---> Assume a natural no. N..
---> Suppose 0<N<9²
Then, if any no. between 0 to 9 can divide it.. But if it doesn't, the no. is a prime no.
Here,
--> we know :-> 0 < 7921 < 90²
Hence, we try dividing 7921 by all primes falling b/w 0 and 90...
Now,
--> Since we know it is a square,
---------> we can shorten the range :-> 85² < 7921 < 90²
And so we divide 7921 by 86,87,88,89 :->
---> Thus, we get 7921 = 89² <--- Ans..
Hence, 7921 = 89² is the root
---> Assume a natural no. N..
---> Suppose 0<N<9²
Then, if any no. between 0 to 9 can divide it.. But if it doesn't, the no. is a prime no.
Here,
--> we know :-> 0 < 7921 < 90²
Hence, we try dividing 7921 by all primes falling b/w 0 and 90...
Now,
--> Since we know it is a square,
---------> we can shorten the range :-> 85² < 7921 < 90²
And so we divide 7921 by 86,87,88,89 :->
---> Thus, we get 7921 = 89² <--- Ans..
Hence, 7921 = 89² is the root
Answered by
4
89 is the answer...
Hope it helps
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