Question

square root of 9408 by prime factorization method​

Answer 1

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Answer 2

Square root of 9408 is $56 \sqrt{3}$

Step-by-step explanation:

Number = 9408

We are supposed to find square root of 9408 by prime factorization method​

So,

2  |  9408

2  |  4704

2  |  2352

2  |  1176

2  |  588

2  |  294

7   | 147

7  |  21

3  |   3

   |  1

$9408= 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 3$

$\sqrt{9408}=\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 3}$

$\sqrt{9408}=2 \times 2 \times 2 \times 7 \times \sqrt{3}$

$\sqrt{9408}=56 \sqrt{3}$

Hence square root of 9408 is $56 \sqrt{3}$

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