Square root of a perfect square containing 'n' digits has how many digits?
Answers
Answered by
10
Answer:n÷2 if n is even and (n+1)÷2 if n is odd
Step-by-step explanation:
eg.100 here n=3 and sq.rt. of 100 is 10 which satisfies the rule.
1024 here n=4 and sq.rt. of 1024 is 32 this also satisfies the rule. hence proved
Answered by
0
Answer:
najsgfsfwvagayyzjz avsghxhd
Step-by-step explanation:
bavaffajqwpejrhxvzvvBbzzjzjvegauaalwlwppqoqiayeyrhgrd
Similar questions