Question

Square root of a perfect square containing 'n' digits has how many digits?

Answer 1

Answer:n÷2 if n is even and (n+1)÷2 if n is odd

Step-by-step explanation:

eg.100 here n=3 and sq.rt. of 100 is 10 which satisfies the rule.

1024 here n=4 and sq.rt. of 1024 is 32 this also satisfies the rule. hence proved

Answer 2

Answer:

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Step-by-step explanation:

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