Question

square root of an expression ( x-3) find that expression​

Answer 1

Explanation:

Let the expression be y.

Given,

$\mathsf{\sqrt{y}=(x-3)}$

$\mathsf{==>y=(x-3)^2}$

$\mathsf{==>y=x^2-2(x)(3)+3^2}$

∴ $\mathsf{y=x^2-6x+9}$

Hence, the required expression is $\mathsf{x^2-6x+9}$.

Answer: x^2 - 6x + 9

I hope this helps. ^^