Question

Square root of the sum of first 49 natural numbers is

Answer 1

Step-by-step explanation:

Answer is 35

1+2+3+..........................................49 = 1225

root of 1225 is 35

Answer 2

According to the question;

the sum of the first 49 natural numbers by Arithmetic Series

Sum = n × $\frac{x + y}{2}$

where,

• n = total number
• x = First number
• y = last number

Sum = 49 × $\frac{1 + 49}{2}$

sum = 49 × 25

sum = 1225

The square root of 1225 is 35. ( 35 × 35 = 1225)

Another method;

According to the question;

1 + 2 + 3 + ................................ + 49 = 1225

The square root of 1225 is 35. ( 35 × 35 = 1225)

• Natural Number:- Natural numbers are positive integers or non-negative integers that begin with 1 and end with infinity, for example, 1,2,3,4,5,6,7,8,9,10,……,∞.
• Square Root:- A square root is a value that, when multiplied by itself, returns the original number. There are four methods for calculating the square root: prime factorisation, repeated subtraction, long division, and estimation.

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