Question

square root of x+under root of x +under root of x+....​

Answer 1

Answer:

Given equation can be written as,

y=x+y−−−−−√

y2=x+y

Differentiating both sides w.r.t. x,

2ydydx=1+dydx

dydx(2y−1)=1

dydx=12y−1, where y2=x+y and y>0.

Step-by-step explanation:

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