Question

square + Y square is equal to 40 at the point whose is to co-ordinate is 16​

Answer 1

Step-by-step explanation:

x

2

+y

2

=13

2

2

+y

2

=13

y

2

=9

y=±3

∴ In y=mx+c

y=3x=2

∴3=2m+c

c=3−2m----(1)

we know

d=

∣

∣

∣

∣

∣

a

2

+b

2

ax

1

+by+c

∣

∣

∣

∣

∣

y=mx−c=0

(0,0)

13

=

1+m

2

∣0−0−c∣

13

=

1+m

2

c

or c

2

=13(1+m

2

) from (1)

(3−2m)

2

=13(1+m

2

)

9+4m

2

−12m=13+13m

2

9m

2

+12m+4=0

(3m+2)

2

=0∴

m=−2/3

c=3−2m

=3−2(−2/3)

=3+4/3=13/3

∴y=−2/3x+13/3 or

2x+3y=13

(2,3)

(2,−3)

y=mx+c

c=−2m−3

−3=2m+cy−mx−c=0 (0, 0)$$

∣

∣

∣

∣

∣

1+m

2

0−0−c

∣

∣

∣

∣

∣

=

13

c

2

=13(1+m

2

)

(−2m−3)

2

=13+13m

2

or 4m

2

+12m+9=13+13m

9m

2

−12m+4=0

(3m−2)

2

=0

m=2/3

c=−3−2m

=−3−(2/3)

c=

3

−13

y=

3

2x

−

3

13

2x−3y=13

2x+3y=13