Question

squareroot(1+55÷729)=1+x÷27

Answer 1

(1+55÷729)=1+x÷27


$\sqrt{(1 + 55 \div 729)} = \frac{1 + x}{27} \\ \\ \sqrt{1 + \frac{55}{729} } = \frac{1 + x}{27} \\ \\ \sqrt{ \frac{729 + 55}{729} } = \frac{1 + x}{27} \\ \\ \frac{1}{27} \sqrt{784} = \frac{1 + x}{27} \\ \\ 28 = 1 + x \\ \\ \huge\purple {\boxed{ \boxed { \boxed { \boxed { \boxed { \mathfrak{x = 27}} }}}}}$

Answer 2

Answer:

x=1

Step-by-step explanation:

√1+55/729=1+x/27

√729+55/729=1+x/27

√784/729=1+x/27

28/27=1+x/27

28/27=27+x/27

28=27+x

28-27=x

1=x

Therefore x=1