Question

Sridhar calculated the distance between T(5, 2) and R(−4, −1) to the nearest tenth is 9.5 units. Now you find the distance between P (4, 1) and Q (-5, -2). Do you get the same answer that sridhar got? Why?

Answer 1

Hi ,

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Distance between two points

A( x1 , y1 ) and B( x2 , y2 ) =

AB = √ ( x2 - x1 )² + ( y2 - y1 )²

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i ) T( 5 , 2 ) = ( x1 , y1 )

and

R( -4 , -1 ) = ( x2 , y2 )

distance ( TR ) = √ [ ( -4 - 5 )² + ( -1 - 2 )² ]

TR = √ ( - 9 )² + ( - 3 )²

TR = √ 81 + 9

= √ 90

≈ 9.5 ( given )----( 1 )

ii ) P( 4 , 1 ) = ( x1 , y1 )

and

Q( -5 , -2 ) = ( x2 , y2 )

distance ( PQ ) = √[ ( -5 - 4 )² + ( -2 - 1 )²

= √ ( -9 )² + ( -3 )²

= √ 81 + 9

= √ 90

PQ ≈ 9.5 [ from ( 1 ) ]


Therefore ,

TR = PQ

I hope this helps you.

: )

Answer 2

Answer:

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