Sridharacharya formula to find roots of a quadratic equation
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Answered by
1
the formula is -
-b+-√ b^2 - 4ac÷ 2a
-b+-√ b^2 - 4ac÷ 2a
Answered by
1
ax^2 + bx + c =0
x= -b +√b^2-4ac/2a
hope it helps :)
x= -b +√b^2-4ac/2a
hope it helps :)
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