Question

Srikar says that the order of the polynomial (x2-5) ( x3+1) is 6 Do you agree with him? How?

Answer 1

no i dont agree with him because x^2(x^3)=x^5 and the order of the polynomial is 5 not 6

Answer 2

No, the order of the polynomial is 5.

Step-by-step explanation:

The given polynomial is

p(x)=(x^2-5)(x^3+1)p(x)=(x

2

−5)(x

3

+1)

Using distributive property, we get

p(x)=x^2(x^3+1)-5(x^3+1)p(x)=x

2

(x

3

+1)−5(x

3

+1)

P(x)=x^5+x^2-5x^3-5P(x)=x

5

+x

2

−5x

3

−5

The heights degree of monomial in a polynomial is the degree or order of the polynomial.

From the above polynomial function it is clear that the heights degree of monomial x^5x

5

is 5.

Therefore the order of the polynomial is 5 and Srikar is wrong.