Question

Srishti has a total of ₹780 as currency notes in the denominations of ₹10, ₹ 20 and ₹50. The ratio of the numbers of ₹50 notes and ₹10 notes is 3:2. If she has total of 32 notes, how many notes of each denominations she has?

Answer 1

Solution :-

Let us Assume That, numbers of ₹50 notes and ₹10 notes is 3x & 2x .

Than,

→ Number of ₹ 20 coins = 32 - (3x + 2x) = (32 - 5x)

Now, According to Question Total Currency is ₹780.

So,

→ 10*2x + 20(32 - 5x) + 50*3x = 780

→ 20x + 640 - 100x + 150x = 780

→ 70x = 780 - 640

→ 70x = 140

→ x = 2 .

Hence,

→ Total coins of ₹10 = 2x = 2*2 = 4 (Ans.)

→ Total coins of ₹20 = 32 - 5x = 32 - 5*2 = 22 (Ans.)

→ Total coins of ₹50 = 3x = 3*2 = 6 (Ans.)

Answer 2

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$\huge\tt{GIVEN:}$

• Shristi has ₹780 in the denominations of ₹10,₹20,₹50.
• The ratio of ₹50 & ₹10 notes is 3:2
• She has total of 32 notes.

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$\huge\tt{TO~FIND:}$

• How many notes of each denominations?

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$\huge\tt{SOLUTION:}$

Let the number of ₹50 notes be 3x and ₹10 notes be 2x

Then,

↪Number of ₹20 notes = 32 - (3x+2x)

↪Number of ₹20 notes = (32 - 5x)

$\rule{200}2$

So, Let's make an equation,

↪10 × 2x + 20(32 - 5x) + 50 × 3x = ₹780

↪20x + 20(32 - 5x) + 50 × 3x = ₹780

↪20x + 640 - 100x + 150x = ₹780

↪170x - 100x = 780 - 640

↪70x = 140

↪x = 140/70

↪x = 2

As we found the value of x, we can find the numbers of notes of each denominations....

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So,

↪Total number of notes of denomination of ₹10 = 2x

↪Total number of notes of denomination of ₹10 = 2 × 2

↪Total number of notes of denomination of ₹10 = 4

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↪Total number of notes of denomination of ₹20 = 32 - 5x

↪Total number of notes of denomination of ₹20 = 32 - 5×2

↪Total number of notes of denomination of ₹20 = 32 - 10

↪Total number of notes of denomination of ₹20 = 22

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↪Total number of notes of denomination of ₹50 = 3x

↪Total number of notes of denomination of ₹50 = 3 × 2

Total number of notes of denomination of ₹50 = 6

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