SRQ is a straight line.RSP=63° and SRP=82°.find PRQ
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Sum of angles of a triangle = 180°
Hence,
RSP + SPR + PRS = 180°
> 63° + 82° + PRS = 180°
> 145° + PRS = 180°
> PRS = 180° - 145°
> PRS = 35°
PRS + PRQ = 180° (Linear Pair)
> 35° + PRQ = 180°
> PRQ = 180° - 35°
> PRQ = 145°
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Answer:
In ΔPSR,
<SPR+<PSR+<PRS=180°
82°+63°+<PRS=180°
145°+<PRS=180°
<PRS=180°-145°
<PRS=35°
<PRS+<PRQ=180°
35°+<PRQ=180°
<PRQ=180°-35°
<PRQ=145°
OR
<PRQ=<SPR+<PSR(Exterior angle sum property)
<PRQ=82°+63°
<PRQ=145°
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