sry for the handwriting it's my teacher's handwriting
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Hello there,:-)
Here's the answer:-
Length of pole = 8 m 40 cm = 840 cm.
Length of shadow is 4 m 60 cm = 460 cm
As the pole forms right angle with the ground, the structure is something like a right angle triangle.
So,
Hypotenuse = root of 840 cm^2 - 460 cm^2
[Putting the formula for a^2 - b^2 = (a+b)(a-b)]
= root of (840+460)(840-460)
= root of 1300 x 180
= 483.73 approx = 484 approx.
So,
(I) Given,
Length of pole = 12 m 25 cm = 1225 cm
[ I apologise some problem has occurred ]
I hope it helped somehow upto this much. Sorry :'(
Here's the answer:-
Length of pole = 8 m 40 cm = 840 cm.
Length of shadow is 4 m 60 cm = 460 cm
As the pole forms right angle with the ground, the structure is something like a right angle triangle.
So,
Hypotenuse = root of 840 cm^2 - 460 cm^2
[Putting the formula for a^2 - b^2 = (a+b)(a-b)]
= root of (840+460)(840-460)
= root of 1300 x 180
= 483.73 approx = 484 approx.
So,
(I) Given,
Length of pole = 12 m 25 cm = 1225 cm
[ I apologise some problem has occurred ]
I hope it helped somehow upto this much. Sorry :'(
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