Physics, asked by XENSILVER, 8 hours ago

ss of Copper PleceVolume of Copper Piece Mass of Water/ Volume of Water Mass of Copper Piece/Volume of Copper Piece Mass of Water displaced by copper piecel Volume of displaced Water Since Hence, The volume of displaced water Volume of copper piece Specific gravity of copper Mass of copper Piece in air mass of water dispaced Weight of copper piece in air V Weight of Water displaced But weight of water displaced is equal to the loss of weight of copper piece in water, hence Specific gravity of copper Weight of copper in air loss of weight of copper piece in water Specific gravity W W, - W₂ Where WA = weight of copper piece in air W2 = weight of copper piece in water From the above equation we can find the density of copper. aisal Model Test Papers Physics IX-X 163 Properties of Matter.​

Answers

Answered by sachanparth693
1

hi

Explanation:

Correct option is

A

13 cc

Volume of the piece =

Density of copper

Mass of it in air

V

copper

=

88

264

=30 cc

Volume of water displaced =

fw×g

Buoyant Force

Buoyant Force = Charge in weight

=264 g−221g=43g

Volume of water displaced =

1 gm/cc×g

43g

=43 cc

Volume of piece including cavity = Volume of water displaced

V

Total

=43 cc

Volume of cavity =V

Total

−V

Copper

=43−30

=13 cc

Similar questions