Question

Ssssssolve Q-7 b plz be fast with clear steps

Answer 1

x²-x-6<0
x²-3x+2x-6<0
x(x-3)+2(x-3)<0
x-3<0
x<3
x±2<0
x<-2
-1 , 0 , 1 , 2

Answer 2

GIVEN:-

.

${x}^{2} - x - 6 < 0$

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SOLUTION:-

.

${x}^{2} + 2x + 3x - 6 < 0$

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THAN:-

.

$x \times (x + 2) - 3(x + 2) < 0$

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THAN:-

.

$(x + 2) \times (x - 3) < 0$

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THAN THE THREE STEPS ARE IN THE ATTACHMENT ↑↑↑↑↑↑↑↑↑