Question

ST ll QR, PS=2.4CM, PS=3.2cm, PT=4.8cm, TR=4.8cm. THEN FIND PQ

Answer 1

Answer:

I don't under stand your question

Answer 2

Step-by-step explanation:

Given

In figure

ST // QR ,

• PS = 2.4 cm
• PT = 3.2 cm
• TR = 4.8 cm

In ∆PST & ∆PQR

• Angle PST = Angle PQR (:. ST // QR)
• Angle PTS = Angle PRQ (:. ST // QR)
• Angle P = Angle P (:. Common angle)

:. ∆PST ≅ ∆PQR

$= > \frac{PS}{SQ} \: = \: \frac{PT}{TR}$

• $\frac{2.4}{SQ}$ $\frac{3.2}{4.8}$

• SQ = $\frac{(2.4~~×~~4.8)}{3.2}$

• SQ = 3.6 cm

:. PQ = PS + SQ

• 2.4 + 3.6
• 6 cm

:. The value of PQ = 6 cm.