st parllel rq,ps=3cmand sr=4cm . find the ratio of the area of ^ pst to the area of ^ prq.
Swarup1998:
Is it a Trapezium? Or a parallelogram? Or anything else? Can you make the problem clear?
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I hope that this will help you.
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Answer:
9:49
Step-by-step explanation:
Given
ST || RQ
PS= 3 cm
SR = 4cm
Proof :--
ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²
ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²
ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49
Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49
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