Math, asked by sunitamehra0029, 9 months ago

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1. 2x – 3; 6x3 + x2 - 19x + 6​

Answers

Answered by tuktuki8
0

Answer:

please mark as brain list

Step-by-step explanation:

Question :

6x3 + x2 - 19x + 6 by 2x - 3

Factorize :2x^(4)+x^(3)-14x^(2)-19x-6

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f(x)=2x+3 if x2

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If a B but 2- 5a 3, 2- sp 3, then the equation having the roots B and B (B) 3x 19x 3 0 (D) x 16x 1 ELAS A) 2 19x 3 one root of the quadratic equation (a 5a 3)x2 (3 19x

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7x^2-19x-6=?

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2x^(4)15x^(3)+19x^(2)-15x+2=0 is a

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-6x3 xx 5x^2

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(4x^(2) + 19x^(2) + 25) div (2x^(2) - x + 5) = "_________" .

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Q.Obtain all the zeroes of the polynomial f(x)=2x^(4)+x^(3)-14x^(2)-19x-6 if two of its zeroes are -2 and -1

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Obtain all zeros of the polynomial f(x)=2x^(4)+x^(3)-14x^(2)-19x-6, if two of its zeros are -2 and 1

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Find all points of discontinuity of f, where f is defined by f(x)={2x+3,quad if x2

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2.10 The radii of the circles x2 + y2 = 1, x2 + y2 – 2x – 6y = 6 and x2 + y2 - 4x - 12y = 9 are in(A)AP.(B)GP.(C) H.P.(D) None

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Give possible values for length,breadth and height of the cubical whose volume is 2x(6x3-4x)

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Solve the equation for x2^(2x+1)=17.2^(x)-2^(3)

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Function f(x)=2x^(3)-9x^(2)+12x+29 is monotonically decreasing when (a) x2( c) x>3(d)'1

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x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0

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The value of a for which x^(3)-7x+5 is a factor of x^(5)-2x^(4)-4x^(3)+19x^(2)-31x+21+a

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Find k so that (lim)_(x rarr2)f(x) may exist,where f(x)={2x+3,x2

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The largest value of 2x^(3)-3x^(2)-12x+5 for -2 le x le x2 occurs when

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Expand the following by binomial theorem: ((2x)/3-3/(2x))^6

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Answered by balainiyan2020
0

Answer:

-245.75

Step-by-step explanation:

1.2×-3;63+×2-19×+6=-245.75

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