Question

st
The principle
value
is
of log(i^1/4)​

Answer 1

Answer:

we know that according to Eular formula..

$i = {e}^{i \frac{\pi}{2} }$

so

$ln( {i}^{ \frac{1}{4} } ) = \frac{1}{4} ln(i) = \frac{1}{4} ln( {e}^{i \frac{\pi}{2} } ) = i \times \frac{\pi}{2} \times \frac{1}{4} ln(e) = \frac{\pi}{8} i$