Question

Stability Order Of The Following Compounds is:-

PbF4, PbCl4, PbBr4, PbI4​

Answer 1

stability order:

PbF4 > PbCl4 > PbBr4 > PbI4

Explanation:

(as from going F to I, the size of elements increases,resulting less bonding)

Answer 2

Answer:

The order of stability is: $PbF_{4} > PbCl_{4} > PbBr_{4} > PbI_{4}$.

Explanation:

The given compounds: $PbF_{4}$, $PbCl_{4}$, $PbBr_{4}$, $PbI_{4}$

• $PbF_{4}$ = Lead tetrafluoride
• $PbCl_{4}$ = Lead tetrachloride
• $PbBr_{4}$ = Lead tetrabromide 
• $PbI_{4}$ = Lead tetraiodide

The order of stability of the given compounds =?

1. As we go down the group in the periodic table, from fluorine to iodine, the size of the elements increases. ( $F < Cl < Br < I$ )
2. As the size of the elements increases, the bonding decreases.
3. The size of Pb is also big like Cl, Br and I.
4. Due to their bigger sizes, the steric hindrance on the central atom, i.e., Pb, increases.
5. This results in difficulty for the atoms to come close together to form the compound.

Therefore, the order of stability is: $PbF_{4} > PbCl_{4} > PbBr_{4} > PbI_{4}$.