Question

Stacy spent $960 on a dress, a bag and a ring . The dress cost $75 more than the bag . The ring cost thrice as much as the dress. How much money did Stacy spend on the bag ?​

Answer 1

Solution -

It is given that Stacy spent $960 on a dress , a bag and a ring .

The dress costs $75 more than the bag.

The ring costs thrice as much as the dress.

Let us assume that the cost of the bag is $ x .

Now

The cost of the dress -

> (x + 75) $

Therefore the cost of the ring

> $ 3(x + 75)

Now be the total cost is $ 960

> 3( x + 75) + x + 75 + x = 960

> 3x + 225 + 2x + 75 = 960

> 5x + 300 = 960

> 5x = 660

> x = 132 $

The cost of the bag is $ 132 . This is the required answer.

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Answer 2

Answer:

Given :-

Stacy spent 960 on a dress, a bag and a ring . The dress cost $75 more than the bag . The ring cost thrice as much as the dress

To Find :-

Money did Stacy spend on the bag ?

Solution :-

Let us assume

Cost of bag = x

According to the question

Cost of dress = Cost of bag + 75

Cost of dress = x + 75

Cost of ring = 3 × x + 75

Cost of ring = 3(x + 75)

According to the question

Cost of bag + Cost of ring + Cost of dress = 960

x + 3(x + 75) + x + 75 = 960

x + 3x + 225 + x + 75 = 960

5x + 300 = 960

5x = 960 - 300

5x = 660

x = 660/5

x = $ 132