Question

STANDARD 9 ...
MATHEMATICS...
PLEASE SOLVE

Answer 1

$Let\: side \: of \: an \: equilateral \: triangle =a \:cm$

$Height (AD) = 4\:cm \: (given )$

$\implies \frac{\sqrt{3}}{2} a = 4$

$\implies a = 4 \times \frac{2}{\sqrt{3}}$

$\implies a = \frac{8}{\sqrt{3}}\: cm$

$\red{Perimeter \: of \: the \: triangle } \\= 3a\\= 3 \times \frac{8}{\sqrt{3}}\: cm \\= 8 \sqrt{3} \: cm \\= 8 \times 1.732 \\= 13.856 \:cm$

Therefore ,.

$\red{Perimeter \: of \: the \: triangle }\green { = 13.856 \:cm }$

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