Standard coil marked 2 ohm is found to a resistance of 2.118ohm at 30degree Celsius calculate the temperature at which marking in correcting the temperature coefficient of the resistance of the material of the coil is 0.0042degree Celsius
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Answer:2k290.
Explanation: t=300K=300−273=27∘C
R27=R0(1+α×27)
R27=R0(1+α×27)……(i)
∴3.115=R0(1+4.3×10−3×27) ....(i)
and 3=R0(1+4.2×10−3×t)…..(ii)
∴33.115=1+4.2×10−3×t1+4.2×10−3×27
On solving we get t=17.21∘C
=17.21×275=290.2K
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