Question

standard deviations of three numbers 3,6,6 is


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Answer 1

Step-by-step explanation:

The standard deviation would also be k.

Standard deviation means the deviation of all the numbers from the mean.

Let us take w=12, s=13, and p=14, so w+6=18, s+6=19 and w+6=20

The formula for standard deviation is √1/n sum (x-mean)^2

n is same=3, mean of 18,19,20 = 19

(18–19)^2=1

(19–19)^2=0

(20–19)^2=1

This gives us (x-mean)^2, so sum = 1+0+1= 2.

So standard Deviation is √1/3 × 2 = √2/3 = √0.66 = 0.81

Now

mean of 12,13,14 = 13

(12-13)^2=1

(13-13)^2=0

(14–13)^2=1

This gives us (x-mean)^2, so sum = 1+0+1= 2.

So standard Deviation is √1/3 × 2 = √2/3 = √0.66 = 0.81

The same answer

So standard deviation is still k

A mattress you can fall back on.

If the SD of a set of 3 numbers w+6, s+6, p+6 is k, then the SD of w, s and p will also be k only.

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If mean deviation is 12, what is its standard deviation?

What does standard deviation tell you about a data set?

What is standard deviation?

How can a standard deviation divided by mean be useful?

What is difference between standard deviation and mean deviation?

How can I find the standard deviation of non-numerical values?

What is the difference between sample standard deviation and population standard deviation?

What are the mean and standard deviation of the sampling distribution of the mean for N = 16 if a population has a mean of 50 and a standard deviation

Answer 2

We get the standard deviation as √2.

Given,

Sample set = 3, 6, 6

To Find,

Standard Deviation

Solution,

Standard deviation, σ is given as -

σ = ∑ $\frac{\sqrt{(x-u)^2} }{\sqrt{N} }$

where, μ is the mean and N is the total numbers present

μ (Mean) = $\frac{x1+x2+x3}{N}$

μ (Mean) = $\frac{3+6+6}{3}$

μ (Mean) = $\frac{15}{3}$

μ (Mean) = 5

Variance = {∑ (xₙ - μ)²}/N

Variance = {(3 - 5)² + (6 - 5)² + (6 - 5)²}/3

Variance = {(-2)² + (1)² + (1)²}/3

Variance = {4 + 1 + 1}/3

Variance = 6/3

Variance = 2

Standard Deviation = $\sqrt{Variance}$

Standard Deviation = $\sqrt{2}$

Hence, we get the standard deviation as √2.

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