Question

standard electrod potential of ni2+/ni electrode ; if the cell potential of the cell niIni2+(0.01m)ll cu2+(0.1m)l cu is 0.56v given : E0 cu2+ / cu = 0.34v is

Answer 1

Explanation:

0.56= 0.34+ R.P.N

R.P.N = 0.22

reduction potential of nickel=0.

22

oxidation potential of nickel= - 0.22