Standard EMF of a galvanic cell involving 2e transfer is found to be 0.591 V at 25degreecelsius. Calculate equillibrium constant for cell reaction
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Answered by
2
delta G = -RT Lnk
delta G = - nEF
n = 2
E =0.591
F = 96500
nEF =RT LnK
2× 0.591 ×96500/ 8.3 × 298
= lnk
lnk = 46
k = e^46
delta G = - nEF
n = 2
E =0.591
F = 96500
nEF =RT LnK
2× 0.591 ×96500/ 8.3 × 298
= lnk
lnk = 46
k = e^46
Deeks18:
But answer is 10 to the power 20
Answered by
8
Answer:10^20
Explanation: firstly we solve the equation for E and we will get the product 20=logKc
Where Kc being the eq constant.
Now we know that for log value to be 20 the log e has to be 20 times multiple of 10 ie log10^20 hence the answer.
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