Question

Standard enthalpy and standard entropy
changes for the oxidation of ammonia at 298 K
are – 382.64 kJ mol⁻¹ and –145.6 JK⁻¹ mol⁻¹,
respectively. Standard Gibb's energy change for
the same reaction at 298 K is
(a) - 22.1 kJ mol⁻¹ (b) - 339.3 kJ mol⁻¹(c) - 439.3 kJ mol⁻¹ (d) -523.2 kJ mol⁻¹

Answer 1

Answer:

(b) - 339.3 kJ mol⁻¹

Explanation:

Given conditions ⇒

Standard Enthalpy(H) = 382640 J/mole.

Standard Entropy(S) = 145.6 J/mole.

Temperature(T) = 298 K.

Using the Formula,

 G = H - TS

⇒ G = 382640 - 145.6 × 298

⇒ G = 382640 - 43388.8

∴ G = 339.251 kJ/mole.

Answer 2

Answer:

Option b is correct

Explanation:

Standard Enthalpy(H) = 382640 J/mole.

Standard Entropy(S) = 145.6 J/mole.

Temperature(T) = 298 K.

Using the Formula,

 G = H - TS

⇒ G = 382640 - 145.6 × 298

⇒ G = 382640 - 43388.8

∴ G = 339.251 kJ/mole.