Question

standard enthalpy of formation of water is - 286 kJ mol^-1 calculate the enthalpy change for formation of 0.018 kg of water​

Answer 1

Given info : Standard enthalpy of formation of water is -286 kJ/mol.

To find : The enthalpy change for the formation of 0.018 kg of water is ....

solution : standard enthalpy of formation of a compound is the amount of energy released forming one mole of the compound.

here enthalpy of formation of water is -286 kJ/mol. it means, the formation of one mole of water released 286 kJ of energy.

molecular weight of water is 18 g/mol

weight of formed water = 0.018kg = 18g

so no of moles = 18/18 = 1 mole

so enthalpy change for the formation of 0.018kg of water = -286 kJ/mol × 1 mol = -286 kJ

also read similar questions : Calculate the standard internal energy change for the formation of water at 298 K. The (5 ) standard enthalpy of formati...

https://brainly.in/question/750438

Calculate the enthalpy of formation of acetic acid., if it's enthalpy of combustion is 860 kj/mol

https://brainly.in/question/6422746

Answer 2

standard enthalpy of formation of a compound is the amount of energy released forming one mole of the compound.

here enthalpy of formation of water is -286 kJ/mol. it means, the formation of one mole of water released 286 kJ of energy.

molecular weight of water is 18 g/mol

weight of formed water = 0.018kg = 18g

so no of moles = 18/18 = 1 mole

so enthalpy change for the formation of 0.018kg of water = -286 kJ/mol × 1 mol = -286 kJ