Standard enthalpy of vapourisation △vapH⊖ for water at 100°C is 40.66kJmol−1. The internal energy of vaporisation of water at 100°C (in kJmol−1) is :
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Hi-
The answer that I got was.... H2O(l)→H2O(s)
Δn=1−0=1
ΔE=ΔH−ΔnRT
=41−1×8.3×373×10−3=37.9kJ/mol
Ans : (C)
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