Science, asked by crestylmae6903, 1 year ago

Standard enthalpy of vapourisation △vapH⊖ for water at 100°C is 40.66kJmol−1. The internal energy of vaporisation of water at 100°C (in kJmol−1) is :

Answers

Answered by Paris123
13

Hi-

The answer that I got was.... H2O(l)→H2O(s)

Δn=1−0=1

ΔE=ΔH−ΔnRT

=41−1×8.3×373×10−3=37.9kJ/mol

Ans : (C)

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