Question

standard form of3(x+5)+3(y+7)=6​

Answer 1

Answer:

=> x+5+y+7 = 2

=> x+y+10 = 0

Answer 2

$Standard \: form \; of \: 3(x+5)+3(y+7) = 6$

/* Dividing each term by 3, we get */

$\implies x + 5 + y + 7 = 2$

$\implies x + y + 12 - 2 = 0$

$\implies x + y + 10 = 0$

Therefore.,

$\red{ Standard \: form \; of \: 3(x+5)+3(y+7) = 6}$

$\green {is \: x + y + 10 = 0 }$

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