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1. Suppose the masses of the calorimeter, the water in it and the hot object made up of copper
which is put in the calorimeter are the same. The initial temperature of the calorimeter and
water is 30 °C and that of the hot object is 60°C. The specific heats of copper and water are
0.09 cal/(gm "C) and I cal / (gm "C) respectively. What will be the final temperature of
water?
Given: mmmm, T -30°C, T. -60°C T.-?
Using formulo (5), m (60 - T) * 0.09 -m* (T)-30) 1+m* (T.-30) 0.09
(60-T) * 0.09 - (T-30) x 109
60 x 0.9 + 30 x 109 -(0.09 + 1.09) T
T, + 32.29 °C
The final temnerature of water wil be 32.29 °C.​

Answer 1

Answer:

it will be on thmmmmmmmmmmmmmmmmm