Standing at 5 m apart from a vertical pole of height 3 m, Sudha observed a building at the back of the piller that tip of the pillar is in line with the top of the building. If the distance between pillar and building is 10 m, estimate the height of the building. [Here height of Sudha is neglected]
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Let the height of the building AB = h m
Let the height of the pole DE = 3m
Let the distance between the pole and the observer AB = 5m
Let the distance between the building and the pole BD = 10m
Thus, from the triangle ABC
Tan a = 3/5
Now, in triangle ADE
tan α = DE/(AB + BD) = 3/5
= DE/(5 + 10) = 3/5
= DE/15 = DE = (3 )15/5
= DE = 3 × 3
= DE = 9
Therefore, the height of the building is 9m.
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