standing at 5m apart from a vertical pole of height 3m, sudha observed a building behind the the pillar and found that tip is in line with the top of the building. if the distance between pillar and buildings is 10m, estimate the height of the buildings (here height of sudha is neglected)
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Answer:
9 m
Step-by-step explanation:
Let Sudha stand at 'C' and the building is AB.
Let DE be the pole.
Distance between pole and building = 10 m.
So, BE = 10 m.
Sudha is 5 m from Pole. Hence the length BC = CE + BE
⇒ BC = 10 + 5 = 15 m.
Let ∠ABC = Ф.
tan(Ф) = AB/BC = DE/EC
⇒ AB/BC = DE/EC
⇒ H/15 = 3/5
⇒ H = 45/5 = 9 m
The height of building is 9 m.
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Here is ur answer. ...❤❤❤❤
Let AB=hm be the height of the building
CE=3m be height of the pole
CD=5m be the dist between the pole and the observer
BC =10m be the dist between the building and the pole
Angle EDC='a'
From triangle ECD
Tan a = 3/5
In triangle ABD
Tan a= h/15
3/5=h/15
H=3/5 ×15
H =9m
Therefore height of the building is 9m
hope it helps u.....follow me......❤❤❤❤
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