Math, asked by aziz7426, 9 months ago

standing at 5m apart from a vertical pole of height 3m, sudha observed a building behind the the pillar and found that tip is in line with the top of the building. if the distance between pillar and buildings is 10m, estimate the height of the buildings (here height of sudha is neglected) ​

Answers

Answered by Anonymous
17

Answer:

9 m

Step-by-step explanation:

Let Sudha stand at 'C' and the building is AB.

Let DE be the pole.

Distance between pole and building = 10 m.

So, BE = 10 m.

Sudha is 5 m from Pole. Hence the length BC = CE + BE

⇒ BC = 10 + 5 = 15 m.

Let ∠ABC = Ф.

tan(Ф) = AB/BC = DE/EC

⇒ AB/BC = DE/EC

⇒ H/15 = 3/5

⇒ H = 45/5 = 9 m

The height of building is 9 m.

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Answered by swastika07642
13

Answer:

Here is ur answer. ...

Let AB=hm be the height of the building

CE=3m be height of the pole

CD=5m be the dist between the pole and the observer

BC =10m be the dist between the building and the pole

Angle EDC='a'

From triangle ECD

Tan a = 3/5

In triangle ABD

Tan a= h/15

3/5=h/15

H=3/5 ×15

H =9m

Therefore height of the building is 9m

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