Standing at 5m apart from a vertical pole of height 3m.sudha observed a building at the back of the pillar that tip of the pillar is in line with top of the building.if the distance between pillar and building is 10m,estimate the height of the building
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dongalavenkate:
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Let AB=hm be the height of the building
CE=3m be height of the pole
CD=5m be the dist between the pole and the observer
BC =10m be the dist between the building and the pole
Angle EDC='a'
From triangle ECD
Tan a = 3/5
In triangle ABD
Tan a= h/15
3/5=h/15
H=3/5 ×15
H =9m
Therefore height of the building is 9m
CE=3m be height of the pole
CD=5m be the dist between the pole and the observer
BC =10m be the dist between the building and the pole
Angle EDC='a'
From triangle ECD
Tan a = 3/5
In triangle ABD
Tan a= h/15
3/5=h/15
H=3/5 ×15
H =9m
Therefore height of the building is 9m
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