Question

standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the twer​

Answer 1

[HeY Mate]

Answer:

Question:

The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower.

Solution:

Let AB be the tower and BC be the length of its shadow when sun’s altitude is 60° and DB be the length of the shadow when the angle of elevation is 30°.

Let us assume, AB = h m,

BC = x m

DB = (40 +x) m

=> In right triangle ABC,

tan 60° = AB/BC

√3 = h/x

h = √3 x……….(i)

=> In right triangle ABD,

tan 30° = AB/BD

1/√3 =h/(x + 40) ……..(ii)

=> From (i) and (ii),

x(√3 )(√3 ) = x + 40

3x = x + 40

2x = 40

x = 20

=> Substituting x = 20 in (i),

h = 20√3.

Hence, the height of the tower is 20√3 m.

I Hope It Helps You✌️

Answer 2

Step-by-step explanation:

the height of the tower is 20root3metre