Question

standing waves are produced in 10m long stretched string fixed at both ends. If the string vibrates in 5 segments and wave velocity is 20m/s the frequency is

1- 5hz

2-10hz

3-2hz

4-4Hz

Answer 1

hey here is ur answer...

hope this helps plz mark it brainliest.

Answer 2

n=52lλTμ−−√=52X10μ

=520X 20=5 Hz