Question

star one plz tell me the ans​

Answer 1

Step-by-step explanation:

1.

$x {}^{2} - \frac{3x}{10} - \frac{1}{10} = 0$

$10x {}^{2} - 3x - 1 = 0$

$10x {}^{2} + 2x - 5x - 1 = 0$

$2x(5x + 1) - 1(5x + 1) = 0$

$(2x - 1)(5x + 1) = 0$

$x = \frac{1}{2} \: or \: \frac{ - 5}{2}$

2.

Hope this helps u Please make me as a brainliest

Answer 2

$\huge \bigstar{\underline{\red{\mathfrak Question :}}}$

Solve the following quadratic equation :

• $\tt{m^2 + 5m + 5 = 0}$

$\huge \bigstar{\underline{\green{\mathfrak Answer:}}}$

• $\tt m = \dfrac{( - 5 \pm \sqrt 5 )}{2}$

$\large \bf{\underline{\underline{\mathfrak {Step\: by\: step \:explanation:}}}}$

$\implies \tt{m^2 + 5m + 5 = 0}$

$\implies\tt m^2 + 5m = -5$

$\implies\tt m^2 + 2 \times m \times \dfrac{5}{2} = - 5$

$\implies\tt m^2 + 2 \times m \times \dfrac{5}{2} + \left(\dfrac{5}{2} \right)^2 = \left(\dfrac{5}{2}\right)^2 - 5$

$\implies\tt \left( m + \dfrac{5}{2}\right)^2 = \dfrac{25}{4} - 5$

$\implies \tt \left( m + \dfrac{5}{2}\right)^2 = \dfrac{( 25 - 20 )}{4}$

$\implies \tt \left( m + \dfrac{5}{2}\right) = \pm {\sqrt{\left(\dfrac{5}{4}\right)}}$

$\implies \tt m +\dfrac{5}{2} = \pm{\sqrt{\dfrac{5}{2}}}$

$\implies \tt m = \dfrac{-5}{2} \pm{\sqrt{\dfrac{5}{2}}}$

$\implies \tt m = \dfrac{( - 5 \pm \sqrt 5 )}{2}$