Starring from rest Rohan pressed the accelerator of his car to attain a velocity of 12 m / s in 30 s then he applies brakes such that the velocity of the car comes down to 8 m / s in the next 5 s. Calculate the acceleration of the car in both the cases
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u =0
v = 12m/s
t = 30s
a=?
1st case
a = (v - u) / t
= (12 - 0) / 30
= 12/30 = 0.4m/s^2
2nd case
u = 12m/s
v = 8
t = 5s
a=?
a = (v - u) / t
a = (8 - 12) / 5
a = - 0.8m/s^2
Thanks
v = 12m/s
t = 30s
a=?
1st case
a = (v - u) / t
= (12 - 0) / 30
= 12/30 = 0.4m/s^2
2nd case
u = 12m/s
v = 8
t = 5s
a=?
a = (v - u) / t
a = (8 - 12) / 5
a = - 0.8m/s^2
Thanks
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