Question

Start with the primitive unit vectors of face centered cubic lattice with cubic lattice constant, a_0a0​,

\vec{a}_1 = \frac{a_0}{2} (\hat{x} + \hat{y})a1​=2a0​​(x^+y^​)

\vec{a}_2 = \frac{a_0}{2} (\hat{y} + \hat{z})a2​=2a0​​(y^​+z^)

\vec{a}_3 = \frac{a_0}{2} (\hat{z} + \hat{x})a3​=2a0​​(z^+x^)

and show that the reciprocal lattice of face-centered cubic lattice is body-centered cubic lattice. Briefly explain how the unit vectors you obtained describe a body-centered cubic lattice.

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Answer 1

Answer:

Exercise problems 3: Crystal structure

For simple cubic, the conventional unit cell is the primitive unit cell but for ... The translation vector is, →Thkl= 4.12e-10 ˆx+ 0 ˆy+ 0 ˆz [m].