Question

Starting at home, Ishaan traveled uphill to the gift store for 181818 minutes at just 101010 mph. He then traveled back home along the same path downhill at a speed of 303030 mph.
What is his average speed for the entire trip from home to the gift store and back?

Answer 1

Answer:

202020 mph

Step-by-step explanation:

this is the answer as per me

Answer 2

The average speed of Ishaan for the entire trip from home to the gift store and back is 151515 mph.

Step-by-step explanation:

When Ishan traveled uphill to gift store:

1. Ishaan traveled uphill to the gift store for 181818 minutes at just 101010 mph.
2. Then the distance covered from home to shop is given by

     $\Rightarrow Speed= \frac{Distance}{Time}$

     $\Rightarrow Distance= Speed \times Time$

     Here, Speed = 101010 mph and time = 181818 minutes = $\frac{181818}{60}$

     $\Rightarrow Distance= 101010 \times \frac{181818}{60}$

     $\Rightarrow Distance= 101010 \times 30303$ meters

When Ishan traveled back home along the same path downhill:

1. He then traveled back home along the same path downhill at a speed of 303030 mph.
2. Then the time taken is given by

     $\Rightarrow Speed= \frac{Distance}{Time}$

     $\Rightarrow Time= \frac{Distance}{Speed}$

     Here, Speed = 303030 mph = $\frac{303030}{60}$ mpmin and distance = $101010 \times 30303$

     $\Rightarrow Time= 101010 \times 30303 \times \frac{60}{303030}$

     $\Rightarrow Time= 60606$ minutes

The average speed for the entire trip from home to the gift store and back is given by

1. Total distance =  $2 \times 101010 \times 30303$ meters
2. Total time = 181818 minutes + 60606 minutes = 242424 minutes

     $\Rightarrow Speed= \frac{2 \times 101010 \times 30303}{242424}$

     $\Rightarrow Speed= \frac{2 \times 101010 \times 30303}{242424} \times 60$

    $\Rightarrow Speed= 151515$ mph

The average speed for the entire trip from home to the gift store and back is 151515 mph.