Starting distance is 2000km and final distance is 2400 km , time is 8 hours then calculate average speed in km h^-1 and m s^ -1
Answers
Given that, starting or initial distance is 2000km and final distance is 2400 km.
We have to find the average speed in km/hr and m/s.
Total distance covered = Final distance - Initial distance
= (2400 - 2000) km
= 400 km
Also given time is 8 hr.
Now,
Average speed is defined as the ratio of total distance covered with respect to total time taken. While average velocity is defined as the ratio of total displacement with respect to total time taken.
So,
Average speed = (Total distance covered)/(Total time taken)
= 400/8 = 50 km/hr
To convert km/hr into m/s. Multiply the value by 5/18.
Average speed = 50 × 5/18 = 13.89 m/s
Therefore, the average speed in km/hr is 50 km/hr and in m/s is 13.89 m/s.
Answer:2400km , 2000km , t=8hrs
so the distance is 2400-2000=400km
speed(avg) =400/8=50kph
Explanation:
speed(avg)= total distance / total time
In this question the initial distance is given as 2000km and final is 2400km , but we need to find the avg. speed of the of the distance travelled in between.