Starting from A, Paheli moves along a rectangular path
ABCD as shown in figure. She takes 2 min to travel each
side. Plot a distance-time graph and explain whether the
motion is uniform or non-uniform.
Answers
Answer:
It is non uniform..
Explanation:
because In rectangle Two opposite sides are greater than the other two opposite sides (here path).
let us suppose that AB = CD ( length ) and BC = DA ( breadth)
clearly,
AB and CD is greater than BC and DA.
According to question, Paheli takes 2 minute for each turn..
Let Paheli covers AB first,
- Speed = AB/ 2 min
Then Paheli covers BC second,
- Speed = BC/ 2 min
Now, since AB is greater than BC means paheli is here faster In AB as compared with BC.
This will again the same for every interval..
Means
motion is getting faster, slower at every turn.
i.e., Non uniform motion..
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Answer:
x-axis represents time in minutes and y-axis represent distance in the meter.
Paheli starts from position A and go to point B in 2 min so distance cover is 8 m.We mark point (A) 2 min on axis and point (C) on y-axis then we draw a line passing to pt(A) parallel to the y-axis and one more line passing to pt(C) parallel to the x-axis. Where the two-line interest will be marked as pt(B). Join the pt(B) and pt(O). This line represents a graph of one side
Similarly, we do for all the side.
Speed of Paheli will moving alongside AB is (distance/time) = 8/2m/min = 4 m/min
Here the unit is meter/minute.
Speed along side BC is = 6/2 = 3 m/min
Speed alongside CD is = 8/2= 4 m/min
Speed along side DA is = 6/2= 3 m/min
So, we find that Paheli speed is not the same in the whole journey.
Motion is nonuniform.
Nonuniform can also be found from the distance-time graph, here line is not straight so it is non-uniform motion.x-axis represents time in minutes and y-axis represent distance in the meter.
Paheli starts from position A and go to point B in 2 min so distance cover is 8 m.We mark point (A) 2 min on axis and point (C) on y-axis then we draw a line passing to pt(A) parallel to the y-axis and one more line passing to pt(C) parallel to the x-axis. Where the two-line interest will be marked as pt(B). Join the pt(B) and pt(O). This line represents a graph of one side
Similarly, we do for all the side.
Speed of Paheli will moving alongside AB is (distance/time) = 8/2m/min = 4 m/min
Here the unit is meter/minute.
Speed along side BC is = 6/2 = 3 m/min
Speed alongside CD is = 8/2= 4 m/min
Speed along side DA is = 6/2= 3 m/min
So, we find that Paheli speed is not the same in the whole journey.
Motion is nonuniform.
Nonuniform can also be found from the distance-time graph, here line is not straight so it is non-uniform motion