Question

Starting from a stationary point Rahul padels a cycle
to attain a velocity of 6m/s in 30s. Calculate the acceleration
of its cycle​

Answer 1

Answer:

Acceleration = 0.2 m/s²

Explanation:

Acceleration= change in velocity/time

Change in velocity = 6-0=6

so a = 6/30= 1/5 = 0.2 m/s²

Answer 2

Answer:-

★ Given:-

• u = 0m/s {starting from rest}

• v = 6m/s

• t = 30s

Here;

▪︎u = initial velocity

▪︎v = final velocity

▪︎t = time

★ To Find:-

• a = acceleration

★ Formula Used:-

• Acceleration = ( v - u ) ÷ t

★ Solution:-

Acceleration = ( v - u ) ÷ t

By putting the given values

Acceleration

= ( 6 - 0 ) ÷ 30

= 6 ÷ 30

= 1 ÷ 5

= 0.2 m/s²

∴ Acceleration of its cycle is 0.2 m/s²

★ Formula to be remembered:-

▪︎Acceleration = ( v - u ) ÷ t

▪︎Speed = Distance ÷ time

▪︎Velocity = Displacement ÷ time

▪︎Average Velocity = ( u + v ) ÷ 2

▪︎Average speed = Total speed ÷ total time