Starting from a stationary position, a car artains a velocity of 6m/s in 30s. Find the acceleration of car.
Answers
Given:
• Initial velocity (u) = 0m/s [Starting from a stationary position]
• Final velocity (v) = 6m/s
• Time taken (t) = 30s
To calculate:
• Acceleration (a)
Calculation:
By using first equation of motion :
- v = u + at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Inserting values :
→ 6 = 0 + ( a × 30 )
→ 6 = 0 + 30a
→ 6 = 30a
→ 6/30 = a
→ 1/5 m/s² = a
Henceforth, acceleration of the car is 0.2 m/s².
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More information!
Equations of motion:
- v = u + at
- s = ut + ½at²
- v²– u² = 2as
Where,
★ v = final velocity = m/s
★ u = initial velocity = m/s
★ a = acceleration = m/s²
★ s = distance/displacement = m
★ t = time = sec
Remember that!
- When a body starts from rest, its initial velocity is 0.
- When a body comes to stop or applies breaks, its final velocity is 0.
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Given:
• Initial velocity (u) = 0m/s [Starting from a stationary position]
• Final velocity (v) = 6m/s
• Time taken (t) = 30s
To calculate:
• Acceleration (a)
Calculation:
By using first equation of motion :
v = u + at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Inserting values :
→ 6 = 0 + ( a × 30 )
→ 6 = 0 + 30a
→ 6 = 30a
→ 6/30 = a
→ 1/5 m/s² = a
Henceforth, acceleration of the car is 0.2 m/s².
▬▬▬▬▬▬▬▬▬▬▬
More information!
Equations of motion:
v = u + at
s = ut + ½at²
v²– u² = 2as
Where,
★ v = final velocity = m/s
★ u = initial velocity = m/s
★ a = acceleration = m/s²
★ s = distance/displacement = m
★ t = time = sec
Remember that!
When a body starts from rest, its initial velocity is 0.
When a body comes to stop or applies breaks, its final velocity is 0.
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